Calculation of Quantity of Cement, Sand and Brick in Wall

Calculation of Quantity of Cement, Sand and Brick in Wall


In building construction, there is 75 percent brickwork and in 55% there is beam, column, slabs, and footings. Brickwork means making a wall or room. Bricks come in numbers while mortar is mixture of cement and sand. Cement comes in bag and one bag has a mass of 50 kg. 
Suppose a wall having these dimensions - length = 1 m, width = 1 m and height = 1 m 
Volume = 1 m x 1 m x 1 m = 1 m3 
Estimation of quantity of bricks needed:
Dimension of 1 brick (“with no mortar in meter”) = 0.19 m x 0.09 m x 0.09 m = 0.001539 m3 
Dimension of 1 brick (“with mortar in meter”) = 0.20 m x 0.10 m x 0.10 m = 0.002 m3 
Quantity of bricks = wall volume/ 1 brick volume (with mortar) = 1 m3/0.002 m3 = 500 numbers 
Estimation of mortar quantity: 500 brick
 Volume (“with no mortar”) = 500 x 0.001539 = 0.7695 m3 
Wet Mortar Volume = wall volume – 500 bricks volume (‘with no mortar’) = 1 – 0.7695 = 0.2305 m3 Dry Mortar = 1.33 x 
Wet Mortar Volume = 1.33 x 0.2305 = 0.3065 m3 [subsequent to water addition, mortar volume lessens.] Mortar ratio = 1:6, where 1 points to cement and 6 indicates sand 
Cement volume needed = 1/(1 +6) x Dry Mortar Volume = 1/7 x 0.3065 = 0.0437 m3 
Cement mass in kg = Density x Volume = 1440 x 0.0437 = 62.928 kg 
One bag of cement mass = 50 kg 
Quantity of cement bags required = 62.928/50 = 1.258 bags 
Sand volume needed = 6/(1+6) x dry mortar volume = 6/7 x 0.3065 = 0.2627 m3 = 9.278 ft3

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