EXAMPLE:
Preparing a bar bending schedule of two way slab. The slab size is 3 by 4 reinforcement is 16 mm@150 mm and 10 mm@200 mm c/c shorter and longer span direction respectively. Assume the clear cover is 20 mm?
Bars that are placed in shorter span is called main bars and in longer span it is called a distribution bar.
Main bars:
First, we find out the total no of bars in the shorter span
No of bars
= Total span /spacing
= 3960 mm/150 mm
= 26.4 say 27 No’s of bars
CUTTING LENGTH:
As bar is placed in shorter span which is 3 m.
= Total length of span – 2 x clear cover
= 3000 – 2 x 20
= 2960 mm or 2.960 m Ans…
So we have total 27 No’s of main bars,
Total length:
= 27 x 2.960 m
= 79.92 m Ans…
Weight:
= d2/162 x length
= 16 x 16/162 x 79.92
= 126.2 kg Ans…
Distribution bar:
No of bars
= total span /spacing
= 2960 mm/200 mm
=15.8 say 16 No’s
As bar is placed in longer span which is 4 m
CUTTING LENGTH:
= total length – 2 x clear cover
= 4000 – 2 x 20
= 3960 mm or 3.960 m
So we have total 16 No’s of distribution bars so the total length is
Total length:
= 3.960 x 16
= 63.36 m long bar
Weight:
= d2/162 x length
=10 x 10/162 x 63.36
= 39.1 kg
Total weight of bars:
= weight of main bar + distribution bar
= 126.2 + 39.1
= 165.3 kg Ans…
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